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The correct Answer is:15
Total number of numbers formed by the digits 1, 2, 3, 4, 5 without repetition is 5!=120. Now we know that a number is divisible by 4 if the number placed at its last two digits is divisible by 4. So that last two digits can be 12, 24, 32 or 52, i.e., they can be filled in 4 ways. There are 3!=6 ways of filling the other three places.
Therefore, the favorable numberof ways is 4×6 = 24 ltbgt Hence, the required probability is
P=Favorable no. of casesExhaustive no. of cases=24120=15
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Updated on:21/07/2023
Class 12MATHSPROBABILITY
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