Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even? (2024)

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Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even? ›

Summary: The number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated is 120. Among them, 48 are even.

Hence the total number of 4 digit numbers are = 5C4 × 4! =120.

Required number of ways =16+18+8+2=44 ways.

The number of 4-digit numbers that can be made with the digits 1,2,3,4 and 5 in which at least two digits are identical, is. 505.

The answer is 120 four-digit even integers. It turns out there are 120 such positive numbers. (Double that if you allow negative numbers.)

That gives us 4×3×2×1=4! =24 numbers.

Hence total number of permutations = 9×504=4536. Q. How many 4-digit numbers are there with no digit repeated?

II : The sum of all four digit numbers that can be formed with 1,2,3,4 so that no digit being repeated in any number is 66660.

The correct Answer is:4312

Step by step video, text & image solution for Using digits 1, 2, 3 and 4 only once, find the largest 4-digit number that is divisible by 4. by Maths experts to help you in doubts & scoring excellent marks in Class 6 exams.

How many numbers of four digits can be formed from the digits 0, 1, 2, 3, and 4? 48.

How many 4 digit numbers can be made using 1 2 3 4 5 6 and 7 with none of the digits being repeated? ›

How many 4 digit numbers can be made using the \( 1,2,3,4,5,6,7 \) with none of them being repeated?\ nAnswer: 840" Was this answer helpful?

The number of 4 digit numbers formed using the digits 1,2,3,4,5,6,7 which are divisible by 4 is. 100.

= 7 ! 3 ! = 7 × 6 × 5 × 4 = 840.

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Thus, the answer is Option A, 360 different four-digit numbers. Hope this helps!

Answer: There can be total 120 four digit numbers formed by using the digits 1, 2, 3, 5, 8 if repetition of digits is not allowed.

Hence, there are 48 four digit even numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated.

Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120. Now, in half them unit's digit will be bigger than the ten's digit and in half of them it will be smaller.

Therefore, the number of 4-digit numbers based on the above criteria will be 840.

examples. A 4 digit PIN number is selected. What is the probability that there are no repeated digits? There are 10 possible values for each digit of the PIN (namely: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9), so there are 10 · 10 · 10 · 10 = 10⁴ = 10000 total possible PIN numbers.