How many 3 digit numbers can be formed from the digits 1,2,3,4 and 5 , assuming that:i repetition of the digits is allowed?ii repetition of the digits is not allowed? (2024)

FAQs

How many 3-digit numbers can be formed using 1, 2, 3, 4, 5 with repetition? ›

so 60(ans.) Was this answer helpful? (i) repetition of the digit is allowed? (ii) repetition of the digits is not allowed?

Therefore,120 three digits are formed.

Since repetition of digits is allowed, we have 5 choices for each of the 3 digits of each code. Therefore, 5*5*5 = 125 such 3-digit codes are possible.

There are 504 different 3-digit numbers which can be formed from numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 if no repetition is allowed. Note: We can also use the multiplication principle to answer this question.

Thus, 3-digit numbers can be formed in 60 ways without repetition. Q. (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed?

Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120. Now, in half them unit's digit will be bigger than the ten's digit and in half of them it will be smaller.

⇒ Number of ways = 120. ∴ The required number of ways formed using 3- digit number using 1, 2, 3, 4, 5, 6 is 120. The KPSC will release the notification KPSC Group C recruitment 2024 for various posts. The posts are Junior Engineer, Electrician, Operator, and Health Inspector.

Now these three numbers can be arranged among themselves in ascending order in only 1 way. Hence total no. of ways = 9C3 × 1 = 84.

Thus, by multiplication principle, the required number of 3-digit numbers is 3×20=60.

Answer and Explanation:

We've been given a set of five numbers. By using the above formula, the possibility of forming a 3-digit number from five numbers is: 5 * 5 * 5 = 125.

How many 3-digit numbers can be formed from the digits 1 to 9? ›

for each digit you have 9 possibilities to use a number between 1 and 9, so the total number of 3-digits numbers is 9 * 9 * 9 = 729. when you take all numbers between 1 and 999 (which is the largest 3-digit number), you get 999 in total, obviously.

Total = 4 (choices for hundreds place) × 3 (choices for tens place) × 2 (choices for units place) = 24 different numbers. So, you can create 24 three-digit numbers using the digits 1-5 with the restriction that the digit 2 is not included, and no repetition of digits is allowed.

So, required number of ways in which three digit numbers can be formed from the given digits is 5×4×3=60. How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming that.

Thus, the total number of 3-digit numbers that can be formed = 3 × 2 × 1 = 6.

As we already discussed, the three digits numbers are from 100 (hundred) to 999 (nine hundred ninety-nine). Before we see the list of three digits numbers, first let us discuss how many three digits numbers we have from 100 to 999. Hence, there are 900 three-digit numbers in total.

Detailed Solution

⇒ Number of ways = 120. ∴ The required number of ways formed using 3- digit number using 1, 2, 3, 4, 5, 6 is 120. The KPSC will release the notification KPSC Group C recruitment 2024 for various posts. The posts are Junior Engineer, Electrician, Operator, and Health Inspector.

How many 4 digit numbers can be formed using the digits 1,2,3,4 (repetition is allowed) and what are their sum? Each box represents a digit. There 4 independent choices of 4 digits for the boxes. Therefore, the number of 4 digit numbers that can be formed is 44=256.

900 is the number of 3-digit numbers formed using the digits with repetition. There are 9 numbers, i.e. 111, 222, …, 999 that has 3 numbers being the same.

If you are meaning simply a 3 digit number using digits 0–9 then the answer is 10•10•10 = 1,000 with repetition. 10•9•8 = 720 without repetitions.