I can choose the units place digit ; any of
the four ways 1,2,3,4 if repetition is not
allowed ie. xyz1–,x––y–z–2–,x––y–2–3–,x––y–2–4–
⇒–––4–
For the ten's paced digit; I can choose any 3
of 4 ways 1,2,3,4 if repetition is not allowed
∴4×3⇒––3–4–
For the hundred's place digit I can choose any
2 of 4 ways 1,2,3,4 is arranged to avoid up etc then
⇒–2–3–4–
For the thousands digit place I can any choose
one digit 1–2–3–4– (if npo repetition allowed )
Therefore, total no. of numbers that can we
formed from digit 1,2,3 and 4 when repetition
is not allowed is 1×2×3×4⇒24⇒4!
also, 4P4⇒4!0!⇒24 Ans
FAQs
How many 4 digit numbers can be formed using the digits 1,2,3,4 (repetition is allowed) and what are their sum? Each box represents a digit. There 4 independent choices of 4 digits for the boxes. Therefore, the number of 4 digit numbers that can be formed is 44=256.
How many 4-digit numbers can you form from 1, 2, 3, and 4 with repetition without repetition? ›
Required number of ways =16+18+8+2=44 ways. Q.
How many numbers can be formed from 1, 2, 3, 4, and 5 without repetition when the digit at the unit place must be greater than that in the tenth place? ›
Out of the five possible answers, there is only one that is correct. Without repeating digits, the total number of numbers that may be created from the digits 1, 2, 3, and 5 is 5*4*3*2*!, which equals 5! = 120.
How many 2 digits number can be formed from the digits 1, 2, 3, and 4 when repetition of digits is not allowed? ›
(2) Repetition not allowed : There are 4 options for tens position, and three options for ones position. Therefore, 4×3=12 4 × 3 = 12 2-digit numbers can be formed.
What are all possible combinations of 1 2 3 4 without repeating? ›
If we don't let numbers repeat =24 . If we're talking strictly about combinations (vs permutations) =1 .
How many ways can the digits 1, 2, 3, 4, and 5 be arranged? ›
You can grab any one of them and put them in front of you. So there are five different choices. 120 possibilities. How many ways can the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 be arranged so that no even digit is in its original position?
What is 1 2 3 4 without repetition? ›
How many combinations you can make with 1, 2, 3, and 4 with no repeating digits? The total no of four-digit combinations will be, 4P4 4 P 4 =4!= 4*3*2*1=24.
How many numbers can you make using the digits 1, 2, 3, and 4? ›
No. of numbers that can be formed using all four digits 1,2,3,4=4! =4×3×2×1=24. Was this answer helpful?
How many 4 digit numbers can be formed using 0 1 2 3 4 when repetition is allowed? ›
How many numbers of four digits can be formed from the digits 0, 1, 2, 3, and 4? 48.
How many possible numbers can be formed using the digits 1, 2, 3, 4, 5 each digit not more than once? ›
Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120.
Thus, 3-digit numbers can be formed in 60 ways without repetition. Q. (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed?
How many numbers of four digits can be formed with the digits 1, 2, 3, 4, and 5? ›
Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even? Summary: The number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated is 120.
How many numbers can be formed with digits 1 2 3 4 3 2 1 so that the odd digits always occupy the odd places? ›
Hence, the required number of numbers = (6×3)=18. Q. How many numbers can be formed by using all the digits 1, 2, 3, 4, 3, 2, 1 so that the odd digits always occupy the odd places?
How many numbers of two digits can be formed from the digits 1 2 3 4 5? ›
∴ The number of 2-digit numbers formed from the given set with repetition =5P2+5=20+5=25. Was this answer helpful?
How many four digit numbers can be formed with digits 1 2 3 and 4 and with distinct digits? ›
If I understand your question and what you mean by distinct digits, it would be 4x3x2x1=24.
How many numbers can you make with 1, 2, 3, 4? ›
There are a total of 24 possible combinations that can be made using the numbers 1, 2, 3, and 4. These combinations can be generated by rearranging the digits in different orders.
How many even numbers can be formed from 1 2 3 4 5 without repetition? ›
In total, number of 5 digit even numbers possible = 24 + 24 = 48.
How many 2 digit numbers can you make 1234 without repetition? ›
How many two digit numbers be generated using the digits 0,1,2,3,4 without repeating any digit? 12.
How many 3 digit numbers can be formed using 12345 repetition? ›
So, required number of ways in which three digit numbers can be formed from the given digits is 5×4×3=60. How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming that. (i) repetition of the digits is allowed? (ii) repetition of the digits is not allowed?
